
Question #6f539 + Example - Socratic
The effect of strong base on water is to dramatically increase the concentration of OH^- ions and decrease the concentration of H_3O^+ ions. Water always contains at least small concentrations of …
Question #750c8 - Socratic
Here's what I got. The problem wants you to use the base dissociation constant, K_b, of ammonia, "NH"_3, to determine the percent of ammonia molecules that ionize to produce ammonium cations, …
Question #c548d - Socratic
Question 1: K_ (sp)= 1.1 xx10^ (-11) Question 2: s= 4.9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg ...
Question #645c9 - Socratic
How about these? > (a) With "HCN" The "HCN" adds across the α "C=O" group to form a cyanohydrin. underbrace ("CH"_3"COCOOH")_color (red) ("pyruvic acid") + "HCN" → ...
Question #2e8a6 - Socratic
where the combination ratio is 2:1 then 0,12 mol of nitric acid combine with 0,06 mol of #Ca (OH)_2#, but you have not this quantity, then #Ca (OH)_2# is the limitant reactant and 0,056 mol of it …
Question #845d9 + Example - Socratic
The inductive effect is the effect on electron density in one portion of a molecule caused by electron-withdrawing or electron-donating groups elsewhere in the molecule. In a covalent bond between two …
Question #6b37a + Example - Socratic
The longer the alkyl chain attached to the hydroxyl head, usually the more basic the conjugate base is (and the less nucleophilic).
Question #71ce2 - Socratic
H^+ + OH^--> H_2O when the acid was added to the resulting solution. The H^+ and OH^- react in a 1:1 ratio. This tells us that the number of moles of H^+ used will be equal to the number of OH^- moles in …
Question #71b91 - Socratic
Since water is in excess, "67.7 g MgO" are needed to produce "98.0 g Mg(OH)"_2. Balanced equation "MgO(s) + H"_2"O(l)"rarr"Mg(OH)"_2("s")" Moles magnesium hydroxide Start with the given mass of …
Question #50782 - Socratic
sf(pH=7.04) This is a very dilute solution of NaOH so I would expect the pH to be 7 or very slightly above. Because the concentration is so low we must also take into account the ions that are formed …